What is the physical evidence that collapse actually happens?
Flash news. Nobody has ever produced any.
To the contrast we have lots of lines of evidence that an observer described by quantum mechanics should, upon observing a quantum experiment, be thrown into a superposition of observers. Each of which appears to have observed collapse. The notion is utterly repugnant to our biases so many reject the idea out of hand.
But as we create ever more complex but controlled systems, we can perform ever more elaborate experiments verifying that quantum mechanics works exactly as predicted. At some point if we take seriously the idea that the most successful scientific theory of all time is an accurate description of ourselves, then we have to accept that perhaps there is no collapse after all.
I happen to agree with you, the observer is a quantum system must get entangled with the quantum system, but that still doesn't explain probabilities. If you prepare a system - say sqrt(1/3) spin-down + sqrt(2/3) spin-up, and then observe it, repeatedly, your subjective experience is that you saw spin-down 1/3 of the time, and spin-up 2/3 of the time. I don't understand how purely unitary evolution can explain this. Does it?
> I don't understand how purely unitary evolution can explain this. Does it?
What's the alternative? Assuming unitary evolution and some fairly common-sense axioms about how we'd expect subjective experience to behave (things like: we never experience being in a branch that has amplitude zero; if we experience being in a given branch then we continue to be in that branch), the Born probabilities are the only model anyone's ever come up with for how our subjective experience should go. So what's there to explain?
The alternative is non-MWI theories, which typically introduce the Born rule via new axioms.
Regarding what's to explain, it's quantum randomness (which distills the Born rule objection). Our subjective experience is that we see spin-down 1/3rd of the time, and our theories say the result is otherwise impossible to predict, even in principle. But a deterministic theory cannot produce a random outcome, even a subjective one.
> Our subjective experience is that we see spin-down 1/3rd of the time, and our theories say the result is otherwise impossible to predict, even in principle. But a deterministic theory cannot produce a random outcome, even a subjective one.
Whyever not? What else would you expect the subjective experience of being in a state like 1/sqrt(3)|x> + 2/sqrt(3)|y> to be like?
What would you expect "experiencing along those other bases" to look like? If you expand along a different basis you just get something like: half a chance of experiencing (1/sqrt(3)|x> + 2/sqrt(3)|y>), and half a chance of experiencing (1/sqrt(3)|x> + 2/sqrt(3)|y>), so it amounts to the same thing.
> the structure of the wavefunction is that it divides cleanly into those two branches, and that's true in any basis.
It's not. It only has this Schmidt decomposition in one basis. In other bases there will be cross terms among the basis elements. What you're doing is privileging Schmidt bases as ones that give experiences. In another basis with states w,z say the state will be:
|w>|w> + |z>|z> + |w>|z> + |z>|w>
So you won't be able to give this clean "experience" reading unless you posit we can't experience in things like the w,z basis here and only in Schmidt bases, but then you run into the problem that for real macroscopic systems they won't admit a Schmidt basis.
This seems like the kind of a "vague" Many Worlds where one doesn't look any deeper than pretending a macro-device is a qubit (e.g. no thermal states etc) and looking at one basis. There's a reason properly developed MWI is nothing like this such as the Spacetime State realism of Wallace and Timpson.
Why one would believe in quantum state realism at all is a separate question.
>Of course you can
No you can't, it's a direct consequence of the Kochen-Specker theorem. If the device is treated quantum mechanically and it enters an entangled state of the form you gave then you cannot perform conditioning as the Kochen-Specker theorem, via the non-uniqueness of Hilbert space orthogonal decompositions, prevents an unambiguous formulation of Bayes's law. I can link to papers proving this if you wish.
The fact that we do experiments where we can condition is, in light of this theorem, a demonstration that our measurement devices do not enter into the kind of CHSH states you're giving.
> It's not. It only has this Schmidt decomposition in one basis. In other bases there will be cross terms among the basis elements. What you're doing is privileging Schmidt bases as ones that give experiences. In another basis with states w,z say the state will be: |w>|w> + |z>|z> + |w>|z> + |z>|w>
The state's evolution will be completely equivalent to (a linear superposition of) the evolution of |x>|x> and |y>|y>. That's a physically observable fact that's independent of your choice of basis (it's less obvious in the |z>/|w> basis, but it's still true).
Any physically valid concept of "experience" would have to behave the same way. If your state is equivalent to a linear superposition of "experiencing x" and "experiencing y" then it can be characterised completely in terms of "experiencing x" and "experiencing y", and that's not dependent on your choice of basis (though it may be easier to see in one basis or another).
> No you can't, it's a direct consequence of the Kochen-Specker theorem. If the device is treated quantum mechanically and it enters an entangled state of the form you gave then you cannot perform conditioning as the Kochen-Specker theorem, via the non-uniqueness of Hilbert space orthogonal decompositions, prevents an unambiguous formulation of Bayes's law. I can link to papers proving this if you wish.
> The fact that we do experiments where we can condition is, in light of this theorem, a demonstration that our measurement devices do not enter into the kind of CHSH states you're giving.
I don't know what you're trying to claim here. All the available evidence is that measurement devices, being ordinary physical objects, follow the laws of quantum mechanics, and that includes conditioning behaving as entanglement; if you've got evidence that that's not the case then a Nobel prize awaits. Non-uniqueness is a red herring, because choice of basis does not and cannot change experimental predictions; the basis exists only in the map, not the territory.
The device has to have its contextual observable algebra develop a non-trivial center, not just be entangled as is mentioned in section 5 of the paper I linked. It's well known entanglement alone isn't enough which again is why entanglement alone has been called "pre-measurement" since the 1980s.
Note how this involves hard mathematics, not vague talk about "obvious features of subjective experience". I'll also note that this is a general feature of discussions about this stuff among non-physicists online, especially programming communities like this one, the knowledge is stuck in the late 1970s.
> The state's evolution will be completely equivalent to (a linear superposition of) the evolution of |x>|x> and |y>|y>. That's a physically observable fact that's independent of your choice of basis (it's less obvious in the |z>/|w> basis, but it's still true).
Of course the state can be written in the form |xx> + |yy>. I never denied that. The point is that it can be written in other forms. So it's equally correct to say we'd "experience"
|zz> + |ww> + |zw> + |wz> as to say we'd experience |xx> + |yy> so there's no reason to say we'd "obviously" experience only the latter. Your argument is just "that expansion is always available", but since other expansions are also always available I don't see what the force of this argument is.
Even worse in QFT there isn't an expansion of the form |xx> + |yy> available due to the Reeh-Schleider theorem so your whole construction is moot anyway. Again where is this paper deriving the Born rule from unitarity and basic facts about subjective experience.
> I don't know what you're trying to claim here. All the available evidence is that measurement devices, being ordinary physical objects, follow the laws of quantum mechanics, and that includes conditioning behaving as entanglement.
I'm claiming a consequence of a well known theorem from Quantum Probability. See section 4.2 of this paper https://arxiv.org/abs/1310.1484
Quantum states without superselection (e.g. the entangled states of the form you are considering) leave Bayesian conditioning undefined. As the paper mentions this is a direct consequence of the Kochen-Specker theorem via non-unique orthogonal expansion. It's not a red herring but a rigorously proved theorem.
I don't know what the "Nobel prize" remark is about as it is well known that entanglement doesn't give well-defined conditioning. That's why entanglement with the device alone is called "pre-measurement" in most papers in measurement theory following terminology introduced by Zurek in the early 80s. A good example of the issues with pre-measurement alone is here https://arxiv.org/abs/2003.07464. You can't just treat the device as simply entering some CHSH or GHZ style entangled state and think that solves everything about measurement. It doesn't via the theorem I gave in the paper above (and other issues).
> Of course the state can be written in the form |xx> + |yy>. I never denied that. The point is that it can be written in other forms. So it's equally correct to say we'd "experience" |zz> + |ww> + |zw> + |wz> as to say we'd experience |xx> + |yy> so there's no reason to say we'd "obviously" experience only the latter. Your argument is just "that expansion is always available", but since other expansions are also always available I don't see what the force of this argument is.
If there's a simple description of the wavefunction that's valid then there should be a correspondingly simple description of our experiences that's valid. The fact that there's also a more complicated valid description of the wavefunction is neither here nor there. It's like looking at a basket of 4 apples and asking why your experience doesn't correspond to there being 6 - 2 apples.
> Quantum states without superselection (e.g. the entangled states of the form you are considering) leave Bayesian conditioning undefined. As the paper mentions this is a direct consequence of the Kochen-Specker theorem via non-unique orthogonal expansion. It's not a red herring but a rigorously proved theorem.
Ok, I take your point, saying that we can just condition is overly flippant: if there are cross terms (i.e. entanglement) then classical conditional probability doesn't always accurately describe the behaviour of a system, and of course that's true for a system that includes experimenters inside it. But if we treat an experimenter's conditioning as creating entanglement, like any other QM interaction, and treat the subsequent evolution of the system quantum-mechanically, then there's no problem.
> A good example of the issues with pre-measurement alone is here https://arxiv.org/abs/2003.07464. You can't just treat the device as simply entering some CHSH or GHZ style entangled state and think that solves everything about measurement. It doesn't via the theorem I gave in the paper above (and other issues).
That paper amounts to nothing more than redefining "outcome" as something that cannot be in a superposition, and then using this to argue that it makes their unfounded notion of decoherence physically meaningful. If we assume that experimenters are physical systems that can undergo superpositions like any other, then of course Bell-style "no hidden variables" results apply when those variables are the outcomes of experiments. Big whoop. (Would you find the following argument convincing: "Pre-measuring the polarisation of the photon might have one of two possible results, so it doesn't have an outcome according to any reasonable notion of "outcome". Therefore if any observer has measured a photon's polarisation, a physically meaningful process of decoherence must have occurred"? Put like that it's hopefully obvious that this is nothing more than asserting the primacy of the Copenhagen interpretation).
> Note how this involves hard mathematics, not vague talk about "obvious features of subjective experience". I'll also note that this is a general feature of discussions about this stuff among non-physicists online, especially programming communities like this one, the knowledge is stuck in the late 1970s.
Look, I'm not a big fan of credentialism, but I do have a master's in this from a reputable institution. If working physics has found a compelling argument that there's something mysterious about measurement or experience, then that knowledge hasn't made its way as far as even taught postgrad courses, yet alone the wider public, and the blame for that has to rest with the physicists. (I rather suspect that there's no such argument that has reached any significant consensus among working physicists, and that that the "late 1970s" view in the public sphere reflects that).
Those are the same states so I'm not sure what you mean.
The point is that there is no reason to select out any particular basis over another. You can't just retreat into "well this is the only basis I can experience" because the human sensory apparatus would be able to select out a range of bases in a full unitary account and also the ambiguity of basis decomposition means you can't perform conditioning which we do all the time in experiments.
> Those are the same states so I'm not sure what you mean.
I mean that if you decompose along a different basis than experiencing x/experiencing y, you just get an ensemble of states each of which is a superposition of experiencing x and experiencing y. So you end up with the same thing.
It's like looking at an entangled state (because that's exactly what it is) - if we have a two-particle state like 1/sqrt(2)(|x>|x> + |y>|y>), that behaves like the first particle being in |x> and experiencing the other particle being in |x>, or being in |y> and experiencing the other particle being in |y>, and it might look like that's an artifact of this particular basis decomposition, but it actually isn't - the structure of the wavefunction is that it divides cleanly into those two branches, and that's true in any basis.
> You can't just retreat into "well this is the only basis I can experience" because the human sensory apparatus would be able to select out a range of bases in a full unitary account
A system that's freely interacting will become entangled; whatever we consider ourself is constantly interacting with the rest of ourself, almost by definition.
> also the ambiguity of basis decomposition means you can't perform conditioning which we do all the time in experiments.
Of course you can, and it works exactly the way you'd expect - we already do experiments where some isolated apparatus inside the experiment does something if it detects one thing and something else if it detects something else. Choice of basis is a tool for understanding the wavefunction, not a physically real thing.
See my reply above. You're just declaring we only experience Schmidt bases for no particular reason. Where are you getting this "clear connection" between experience and the decomposition in one particular basis. Do you have a reference?
There are other alternatives such as the derivation of quantum theory within the GPT framework and many other axiomatic derivations.
I've never seen the Born rule derived from unitary evolution and axioms for how subjective experience should work, so I don't even see this as one of the ways.
To paraphrase you, how do we get from probability amplitude to observed frequencies if there is no collapse?
This is were we have to invoke philosophy. Specifically how does consciousness interact with time? The common-sense thinking is that our soul is tied to our body and is traveling forward through time with it. Another way of thinking is that the soul is tied to a given position of the space-time-probability. It does not travel. You today is not the same as you tomorrow or yesterday. The you that observes spin up is not the same you as the one that observes spin down. Your soul is perceiving reality from a randomly chosen vantage point among all the possibilities with which have a compatible body. If we condition on those bodies belonging to experimenters who have observed frequencies, then we get the distribution.
No it can't. There have been many attempts and they don't work. The Born rule is independent of unitary evolution. The closest one can get is to declare that the quantum state is fundamentally a statistical object (i.e. the only information in it is observation probabilities) and then with certain assumptions about the size of the state space you can show that the Born rule is the only possible rule for connecting the state to statistics consistent with the unitary dynamics.
So under the assumption that the state encodes probabilities, state space assumptions and consistency with unitary evolution you get the Born rule. However this is not the same as the Born rule arising dynamically from unitary evolution alone.
Isn't your subjective experience just one probabilistic eigenvalue of a particular combination of operators corresponding to your observation? How does unitary evolution break down here?
It's not unitary evolution breaking down, just that the Born rule isn't a consequence of unitary evolution. They're separate independent hypotheses. In most derivations of QM from an axiomatic basis they're consequences of separate combinations of axioms.
Thanks. Do you by chance have a good source for a gentle introduction into axiomatic QM? Like undergrad level is fine, I've taken basic QM and worked through Griffith's intro book on my own, and I've had a lot of math.
I'd love to read more but my google results aren't turning up a good definitive introduction.
Well in the most common family of interpretations "collapse" isn't an actual physical process, just Bayesian updating. So you wouldn't expect to find physical evidence of it in that sense.
It's true that from the perspective of an external superobserver the quantum state evolves to contain terms for each observer observation state. However since all interference observables turn out to be non-physical for macroscopic systems we get a superselection rule and so the probabilities for different macrostates are classical probabilities and thus reflect simple ignorance of the observer's post measurement state.
There's very little motivation for reading the quantum state "ontically" in the way you are doing.
But this doesn't answer the question. If you claim that all of these possible observers 'exist', how does this have a physical meaning?
This is what I never understood about MWI, in what physical sense can the many worlds be said to exist? Where are they in our universe? What direction would we have to travel to find them? Do they exert gravity on us? If not, then how can we claim that they exist in a physical sense?
No you're thinking of MWI all wrong. Your conception of the universe you exist in as being non-quantum is fundamentally flawed. The universe with the superposition of all the possible observers exists more purely in hilbert space. Sean Carroll has even started to put together a model for how spacetime could emerge from that hilbert space.
So the universes all exist in the same place, since they are the same universe. Your idea of what an observation is, is just an eigenvalue of that corresponding operator.
An object that moves far enough away from us is said to leave the observable universe, because with the continual expansion of space, it or anything it interacts with would have to travel faster than light back toward us in order to have any effect on us. Should we say that objects that leave the observable universe continue to exist? Should we amend our theories to include a new fall-off effect separate from gravity that says things stop existing when they exit our observable universe?
> "Existence isn't based on something affecting our world, obviously - that's just absurdly self-centered."
This is very unfair. This is a niche field with contested interpretations, don't make people feel stupid for asking fair questions.
It's obvious what the other person meant: what does 'our world' and 'other worlds' mean, and how do you know it's not just a figment of your imagination, as a scientific theory must be falsifiable -> i.e. measurable and provable / disprovable somehow.
You should at least point people to reading material before making fun of them.
In physical terms, we do generally define existence that way - for example, we say that time and space didn't exist 'before' the big bang, because there was nothing that could have a position or change. I was thinking of the same notion of existence and how it can be applied to MWI - essentially existence in the physical sense must mean that something is measurable, that it has some effect on the world (perhaps in the past or in the future).
I don't think we do define existence that way. Say you and your friend both go to opposite ends of the visible universe; due to inflation you'll never be able to communicate again.
I suspect most people would say their friend continues to exist. This is very analogous to the many worlds situation.
Thinking about the extreme distances and time spans that entails makes it difficult, and of course relativity has its own "unreasonable" results. Still, they do exist in your past, and they also can assign coordinates in space-time to your current position, even though they are outside your light-cone. On the other hand, you can't meaningfully speak of them existing "now" in relativity, as there is no consistent definition of what "now" means for observers that are space-like separated.
I guess the best answers about MWI is that the other versions of these particles continue to exist at different coordinates in Hilbert space, and that they do interact with each other in observable ways, such as the interference patterns in double-slit experiments.
Speaking as a barely informed enthusiast, we can say they exist in the Occam’s Razor sense that the maths is much less complicated when we assume they do.
I think there’s also an experimental setup, whose name I forget, but which is essentially nested Schrödinger's cat setups: Alice is in a box, Bob is in a box which contains Alice’s box, Carol is outside; Alice goes into superposition of |Alice+> and |Alice->, Bob opens the box and Carol can now demonstrate that Bob is in a superposition of |observing Alice+> and |observing Alice-> instead of the combination of 100%|observing> and a superposition of |Alice+> and |Alice->.
Flash news. Nobody has ever produced any.
To the contrast we have lots of lines of evidence that an observer described by quantum mechanics should, upon observing a quantum experiment, be thrown into a superposition of observers. Each of which appears to have observed collapse. The notion is utterly repugnant to our biases so many reject the idea out of hand.
But as we create ever more complex but controlled systems, we can perform ever more elaborate experiments verifying that quantum mechanics works exactly as predicted. At some point if we take seriously the idea that the most successful scientific theory of all time is an accurate description of ourselves, then we have to accept that perhaps there is no collapse after all.